# 6 Multigroup Analysis

## 6.1 Introduction to Multigroup Analysis

Often in ecology we wish to compare the results from two or more groups. These groups could reflect experimental treatments, different sites, different sexes, or any number of types of organization. The ultimate goal of such an analysis is to ask whether the relationships among predictor and response variables vary by group.

Historically, such a goal would be captured through the application of a statistical interaction. For example, does the effect of pesticide on invertebrate biomass change as function of where the pesticide is applied? This model might look something like this:

$biomass = pesticide * location$

A significant interaction between $$pesticide \times location$$ would indicate that the effect of pesticide applicaiton on invertebrate biomass indeed varies by location. It would of course then be up to the author to use their knowledge of the system to speculate why this is.

In the event that the interaction is not statistically significant, then the author would conclude that the effect of pesticide is invariant to location, and could instead generalize the effects of pesticide such that it’s expected to have the same magnitude of effect regardless of where it’s applied.

A multigroup model is essentially the same principle, but instead of focusing on a single response, the interaction is applied across a structural equation model. In other words, it asks if not just one, but all coefficients are the same or different across groups. In a sense, it can be thought of as a “model-wide” interaction, and in fact, this is how we will treat it later using a piecewise approach.

Of course, you might ask: why not simply fit the same model structure to different subsets of the data? Unfortunately, this would not allow you to identify which paths change based on the group and which do not–which could be key insight. Rather, one would have to compare the magnitude and standard errors of each pair of coefficients manually, rather than through a formal statistical procedure.

The application of multigroup models differs between a global estimation (i.e., variance-covariance-based SEM) and local estimation (i.e., piecewise SEM), but adhere to the same idea of identifying which paths have the same effect across groups and which paths vary depending on the group.

In this chapter, we will work through both approaches, and then compare/contrast the output.

## 6.2 Multigroup Analysis using Global Estimation

Multigroup modeling using global estimation begins with the estimation of two models: one in which all parameters are allowed to differ between groups, and one in which all parameters are fixed to those obtained from analysis of the pooled data across groups. We call the first model the “free” model since all parameters are free to vary, and the second the “constrained” model since each path, regardless of its group, is constrained to a single value determined by the entire dataset.

If the two models are not significantly different, and the latter fits the data well, then one can assume there is no variation in the path coefficients by group and multigroup approach is not necessary. In this case, the output from the constrained model would be reported. If they are, then the exercise shifts towards understanding which paths are the same and which are different. This is achieved by sequentially constraining the coefficients of each path and re-fitting the model.

Let’s illustrate this procedure using a random example using three variables–$$x$$, $$y$$, and $$z$$–in two groups: “a” and “b”:

set.seed(111)

dat <- data.frame(x = runif(100), group = rep(letters[1:2], each = 50))

dat$y <- dat$x + runif(100)

dat$z <- dat$y + runif(100)

In this example, we suppose a simple mediation model: $$x -> y -> z$$, and that all three variables are correlated to some degree so that this path model makes sense.

We can use lavaan to fit the “free” model. The key is allowing the coefficients to vary by specifying the group = argument:

multigroup.model <- '
y ~ x
z ~ y
'

library(lavaan)

multigroup1 <- sem(multigroup.model, dat, group = "group") 

We can then obtain the summary of the multigroup analysis:

summary(multigroup1)
## lavaan 0.6-3 ended normally after 38 iterations
##
##   Optimization method                           NLMINB
##   Number of free parameters                         12
##
##   Number of observations per group
##   a                                                 50
##   b                                                 50
##
##   Estimator                                         ML
##   Model Fit Test Statistic                       0.092
##   Degrees of freedom                                 2
##   P-value (Chi-square)                           0.955
##
## Chi-square for each group:
##
##   a                                              0.049
##   b                                              0.043
##
## Parameter Estimates:
##
##   Information                                 Expected
##   Information saturated (h1) model          Structured
##   Standard Errors                             Standard
##
##
## Group 1 [a]:
##
## Regressions:
##                    Estimate  Std.Err  z-value  P(>|z|)
##   y ~
##     x                 0.771    0.163    4.734    0.000
##   z ~
##     y                 1.080    0.126    8.577    0.000
##
## Intercepts:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.684    0.088    7.745    0.000
##    .z                 0.463    0.140    3.313    0.001
##
## Variances:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.080    0.016    5.000    0.000
##    .z                 0.092    0.018    5.000    0.000
##
##
## Group 2 [b]:
##
## Regressions:
##                    Estimate  Std.Err  z-value  P(>|z|)
##   y ~
##     x                 1.240    0.135    9.182    0.000
##   z ~
##     y                 0.897    0.086   10.465    0.000
##
## Intercepts:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.349    0.078    4.460    0.000
##    .z                 0.612    0.092    6.654    0.000
##
## Variances:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.082    0.016    5.000    0.000
##    .z                 0.081    0.016    5.000    0.000

Note that, unlike the typical lavaan output, the printout is now organized by group, with separate coefficients for each path in each group. Because this model is allowed to vary, the coefficient for the $$x -> y$$ path in group “a” is different, for example, from that reported for group “b”.

Next, we fit the constrained model by specifying the additional argument group.equal = c("intercepts", "regressions"). This argument fixes both the intercepts and path coefficients in each groups to be the same.

multigroup1.constrained <- sem(multigroup.model, dat, group = "group", group.equal = c("intercepts", "regressions"))

summary(multigroup1.constrained)
## lavaan 0.6-3 ended normally after 29 iterations
##
##   Optimization method                           NLMINB
##   Number of free parameters                         12
##   Number of equality constraints                     4
##
##   Number of observations per group
##   a                                                 50
##   b                                                 50
##
##   Estimator                                         ML
##   Model Fit Test Statistic                       9.951
##   Degrees of freedom                                 6
##   P-value (Chi-square)                           0.127
##
## Chi-square for each group:
##
##   a                                              5.541
##   b                                              4.410
##
## Parameter Estimates:
##
##   Information                                 Expected
##   Information saturated (h1) model          Structured
##   Standard Errors                             Standard
##
##
## Group 1 [a]:
##
## Regressions:
##                    Estimate  Std.Err  z-value  P(>|z|)
##   y ~
##     x       (.p1.)    1.046    0.108    9.678    0.000
##   z ~
##     y       (.p2.)    0.960    0.072   13.413    0.000
##
## Intercepts:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y       (.p6.)    0.499    0.061    8.219    0.000
##    .z       (.p7.)    0.570    0.078    7.283    0.000
##
## Variances:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.087    0.017    5.000    0.000
##    .z                 0.094    0.019    5.000    0.000
##
##
## Group 2 [b]:
##
## Regressions:
##                    Estimate  Std.Err  z-value  P(>|z|)
##   y ~
##     x       (.p1.)    1.046    0.108    9.678    0.000
##   z ~
##     y       (.p2.)    0.960    0.072   13.413    0.000
##
## Intercepts:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y       (.p6.)    0.499    0.061    8.219    0.000
##    .z       (.p7.)    0.570    0.078    7.283    0.000
##
## Variances:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.089    0.018    5.000    0.000
##    .z                 0.083    0.017    5.000    0.000

This output is slightly different from the first: the coefficients are reported by group, but they are now the same between groups (e.g., $$x -> y$$ in group “a” = $$x -> y$$ in group “b”). The constrained paths are indicated by a parenthetical next to the path (e.g., (.p1.) for path 1).

Both the constrained and free models fit the data well based on the $$\chi^2$$ statistic, and we can formally compare the two using a Chi-squared difference test:

anova(multigroup1, multigroup1.constrained)
## Chi Square Difference Test
##
##                         Df    AIC    BIC  Chisq Chisq diff Df diff
## multigroup1              2 95.392 126.65 0.0921
## multigroup1.constrained  6 97.251 118.09 9.9508     9.8588       4
##                         Pr(>Chisq)
## multigroup1
## multigroup1.constrained    0.04288 *
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

The significant P-value implies that the free and constrained models are significantly different. In other words, some paths vary while others do not. If the models were not significantly different, then one would conclude that the constrained model is equivalent to the free model. In other words, the coefficients would not vary by group and it would be fair to analyze the pooled data in a single global model.

However, this is the not the case for this example, and we can now undergo the processing of introducing and releasing constraints to try and identify which path varies between groups. In this simplified example, we have two choices: $$x -> y$$, and $$y -> z$$. Let’s focus on $$x -> y$$ first.

We can introduce a single constraint by modifying the model formula and re-fitting the model:

multigroup.model2 <- '
y ~ c("b1", "b1") * x
z ~ y
'

multigroup2 <- sem(multigroup.model2, dat, group = "group")

The string c("b1", "b1") gives the path the name b1 and ensures the coefficient is equal between the two groups (hence the two entries).

If we use a Chi-squared difference test as before:

anova(multigroup1, multigroup2)
## Chi Square Difference Test
##
##             Df    AIC    BIC  Chisq Chisq diff Df diff Pr(>Chisq)
## multigroup1  2 95.392 126.65 0.0921
## multigroup2  3 98.188 126.84 4.8881      4.796       1    0.02853 *
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

…we find that the models are still significantly different, implying that the path between $$x -> y$$ should not be constrained, and that it should be left to vary among groups.

We can repeat this exercise with the second path, $$y -> z$$:

multigroup.model3 <- '
y ~ x
z ~ c("b2", "b2") * y
'

multigroup3 <- sem(multigroup.model3, dat, group = "group")

summary(multigroup3)
## lavaan 0.6-3 ended normally after 34 iterations
##
##   Optimization method                           NLMINB
##   Number of free parameters                         12
##   Number of equality constraints                     1
##
##   Number of observations per group
##   a                                                 50
##   b                                                 50
##
##   Estimator                                         ML
##   Model Fit Test Statistic                       1.523
##   Degrees of freedom                                 3
##   P-value (Chi-square)                           0.677
##
## Chi-square for each group:
##
##   a                                              1.031
##   b                                              0.492
##
## Parameter Estimates:
##
##   Information                                 Expected
##   Information saturated (h1) model          Structured
##   Standard Errors                             Standard
##
##
## Group 1 [a]:
##
## Regressions:
##                    Estimate  Std.Err  z-value  P(>|z|)
##   y ~
##     x                 0.771    0.163    4.734    0.000
##   z ~
##     y         (b2)    0.955    0.071   13.389    0.000
##
## Intercepts:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.684    0.088    7.745    0.000
##    .z                 0.596    0.087    6.858    0.000
##
## Variances:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.080    0.016    5.000    0.000
##    .z                 0.093    0.019    5.000    0.000
##
##
## Group 2 [b]:
##
## Regressions:
##                    Estimate  Std.Err  z-value  P(>|z|)
##   y ~
##     x                 1.240    0.135    9.182    0.000
##   z ~
##     y         (b2)    0.955    0.071   13.389    0.000
##
## Intercepts:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.349    0.078    4.460    0.000
##    .z                 0.557    0.080    6.974    0.000
##
## Variances:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.082    0.016    5.000    0.000
##    .z                 0.082    0.016    5.000    0.000
anova(multigroup1, multigroup3)
## Chi Square Difference Test
##
##             Df    AIC    BIC  Chisq Chisq diff Df diff Pr(>Chisq)
## multigroup1  2 95.392 126.65 0.0921
## multigroup3  3 94.823 123.48 1.5230     1.4309       1     0.2316

In this case, there is not a significant difference between the two models, implying that the is no difference in the fit of the constrained model and the unstrained model, and that this constraint is valid.

Thus, if we were to select a model from which to draw inference, we would select the third model in which $$x -> y$$ is allowed to vary and $$y -> z$$ is constrained among groups. It’s key to note that this model also fits the data well based on the $$\chi^2$$ statistic; if not, then like all poor-fitting path models (multigroup or otherwise), it would be unwise to present and draw conclusions from it.

This exercise of relaxing and imposing constraints is potentially very exploratory and could become exhaustive with more complicated models (i.e., one with lots of paths to potentially constrain/relax). Users should refrain from constraining and relaxing all paths and then choosing the most parsimonious model. Instead, choosing which paths to constrain should be motivated by the question: for example, we might expect some effects to be universal (e.g., temperature on metabolic rate) but not others (e.g., the effect of pesticide may vary depending on the history of application at various sites).

Critically, the degrees of freedom for the model do not change based on the number of groups because coefficients are estimated from variance-covariance matrices with the same dimensions. However, sample size must be sufficiently large to estimate all the parameters with minimal bias. While this is true for all structural equation models, it is especially true where parameters are estimated from covariances derived from different subsets (groups) that do not have the same representative as across the full dataset.

Standardized coefficients also present a challenge. Because variances are likely to be unequal among groups, the standardized coefficient must be computed on a per group basis, even if the unstandardized coefficient is constrained to the global value. Both packages for SEM will do this automatically, so you may notice that the standardized solutions may–and more than often will–vary even among constrained paths.

## 6.3 Multigroup Analysis Using Local Estimation

The goal of multigroup analysis using local estimation is identical to that of global estimation: to identify whether a single global model is sufficient to describe the data, or whether some or all paths vary by some grouping variable. The difference lies in execution: while lavaan is a back-and-forth manual process of relaxing and constraining paths, piecewiseSEM tests constraints and automatically selects the best output for your data.

The upside is that the arduous and somewhat cumbersome process of specifying constraints is taken care of; the downside is that manually constraining particular paths is not possible at this time.

The first step in the local estimation process is to implement a model-wide interaction. In other words, every term in the model interacts with the grouping variable. If the interaction is significant, then the path is free to vary by group; if not, then the path takes on the estimate from the global dataset. In this way, the piecewise multigroup procedure breaks down into a series of classic interaction terms: it is literally and figuratively a model-wide interaction.

Consider our previous example fitted using lavaan. In a piecewise approach, we would first model the interaction between $$x \times group$$ to see whether the effect of $$x$$ on $$y$$ should vary by group:

anova(lm(y ~ x * group, dat))
## Analysis of Variance Table
##
## Response: y
##           Df Sum Sq Mean Sq F value    Pr(>F)
## x          1 8.2740  8.2740 97.9518 2.475e-16 ***
## group      1 0.2772  0.2772  3.2811   0.07321 .
## x:group    1 0.3974  0.3974  4.7051   0.03254 *
## Residuals 96 8.1091  0.0845
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

In this case, the effect of $$x$$ on $$y$$ depends on $$group$$ (a significant interaction term). We would then estimate the effect of $$x$$ and $$y$$ for each subset of the data, and report the coefficients separately. =

Next, we evaluate the effect of $$y$$ on $$z$$ by group:

anova(lm(z ~ y * group, dat))
## Analysis of Variance Table
##
## Response: z
##           Df  Sum Sq Mean Sq  F value Pr(>F)
## y          1 15.8899 15.8899 176.3764 <2e-16 ***
## group      1  0.0366  0.0366   0.4066 0.5252
## y:group    1  0.1271  0.1271   1.4107 0.2379
## Residuals 96  8.6487  0.0901
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

The second interaction between $$y \times group$$ in predicting $$z$$ is non-significant, indicating that the effect of $$y$$ on $$z$$ does not depend on $$group$$. We would then estimate the effect of $$y$$ on $$z$$ using the entire dataset and report that single constrained coefficient across all groups.

The implementation of this approach in piecewiseSEM is very straightforward: first, build the model using psem, then use the function multigroup to perform the multigroup analysis.

library(piecewiseSEM)

pmodel <- psem(
lm(y ~ x, dat),
lm(z ~ y, dat)
)

The multigroup function has an argument group = which, as in lavaan, accepts the column name of the grouping factor:

(pmultigroup <- multigroup(pmodel, group = "group"))
##
## Structural Equation Model of pmodel
##
## Groups = group [ a, b ]
##
## ---
##
## Global goodness-of-fit:
##
##   Fisher's C = 0.301 with P-value = 0.86 and on 2 degrees of freedom
##
## ---
##
## Model-wide Interactions:
##
##   Response Predictor Test.Stat DF P.Value
##          y   x:group       4.8  1  0.0325 *
##          z   y:group       1.0  1  0.2379
##
##  y -> z constrained to the global model
##
## ---
##
## Group [a] coefficients:
##
##   Response Predictor Estimate Std.Error DF Crit.Value P.Value Std.Estimate
##          y         x   0.7712    0.1662 48     4.6387       0       0.5563
##          z         y   0.9652    0.0726 98    13.2931       0       0.6895
##
##     ***
##   c ***
##
## Group [b] coefficients:
##
##   Response Predictor Estimate Std.Error DF Crit.Value P.Value Std.Estimate
##          y         x   1.2404    0.1379 48     8.9963       0       0.7923
##          z         y   0.9652    0.0726 98    13.2931       0       0.8914
##
##     ***
##   c ***
##
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05    c = constrained

If we examine the output, we see the output table of model-wide interactions. It’s important to note that the package uses car::Anova with type = "II" sums-of-squares to estimate the interactions by default, but other types (e.g., type III) are accepted using the test.type = argument (or type I using the base anova function).

As above, only the path from x -> y is significantly different among groups. In this case, the function explicitly reports that the path y -> z constrained to the global model.

Next, as in lavaan, are the coefficient tables for each group. Values that have been constrained are the same between the two models, while the unconstrained path from $$x -> y$$ is different between groups “a” and “b”.

It’s important to note that the standardized coefficients do differ for each group even though the paths are constrained. Again, this is because the variance differs between groups. Thus the standardization:

$$\beta_{std} = \beta*\left( \frac{sd_{x}}{sd_{y}} \right)$$

must consider only the standard deviation of x and y from their respective groups, even though $$\beta$$ is derived from the entire dataset.

Finally, near the top is the global goodness-of-fit test based on Fisher’s C. In this case, global constraints have been added as offset to the tests of directed separation.

For comparison’s sake, let’s look at the output from the lavaan multigroup model and the piecewiseSEM one:

summary(multigroup3)
## lavaan 0.6-3 ended normally after 34 iterations
##
##   Optimization method                           NLMINB
##   Number of free parameters                         12
##   Number of equality constraints                     1
##
##   Number of observations per group
##   a                                                 50
##   b                                                 50
##
##   Estimator                                         ML
##   Model Fit Test Statistic                       1.523
##   Degrees of freedom                                 3
##   P-value (Chi-square)                           0.677
##
## Chi-square for each group:
##
##   a                                              1.031
##   b                                              0.492
##
## Parameter Estimates:
##
##   Information                                 Expected
##   Information saturated (h1) model          Structured
##   Standard Errors                             Standard
##
##
## Group 1 [a]:
##
## Regressions:
##                    Estimate  Std.Err  z-value  P(>|z|)
##   y ~
##     x                 0.771    0.163    4.734    0.000
##   z ~
##     y         (b2)    0.955    0.071   13.389    0.000
##
## Intercepts:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.684    0.088    7.745    0.000
##    .z                 0.596    0.087    6.858    0.000
##
## Variances:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.080    0.016    5.000    0.000
##    .z                 0.093    0.019    5.000    0.000
##
##
## Group 2 [b]:
##
## Regressions:
##                    Estimate  Std.Err  z-value  P(>|z|)
##   y ~
##     x                 1.240    0.135    9.182    0.000
##   z ~
##     y         (b2)    0.955    0.071   13.389    0.000
##
## Intercepts:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.349    0.078    4.460    0.000
##    .z                 0.557    0.080    6.974    0.000
##
## Variances:
##                    Estimate  Std.Err  z-value  P(>|z|)
##    .y                 0.082    0.016    5.000    0.000
##    .z                 0.082    0.016    5.000    0.000
pmultigroup$group.coefs ##$a
##   Response Predictor Estimate Std.Error DF Crit.Value P.Value Std.Estimate
## 1        y         x   0.7712    0.1662 48     4.6387       0       0.5563
## 2        z         y   0.9652    0.0726 98    13.2931       0       0.6895
##
## 1   ***
## 2 c ***
##
## \$b
##   Response Predictor Estimate Std.Error DF Crit.Value P.Value Std.Estimate
## 1        y         x   1.2404    0.1379 48     8.9963       0       0.7923
## 2        z         y   0.9652    0.0726 98    13.2931       0       0.8914
##
## 1   ***
## 2 c ***

You’ll note that the outputs are roughly equivalent (owing to slight differences in the estimation procedures for each package). Critically, the coefficient for the path from $$z -> y$$ is the same in both groups.

## 6.4 Grace & Jutila (1999): A Worked Example

Let’s now turn to a real example from Grace & Jutila (1999). While the original paper fit a far more complicated model than we will, the following simplified model demonstrates the approach well.

In their study, the authors were interested in the controls of on plant species’ density in Finnish meadows. In this worked example, we will consider only elevation and total biomass in their effects on density, plus an effect of elevation on biomass:

Moreover, they repeated their observations in two treatments: grazed and ungrazed meadows. Grazing will serve as the grouping variable for our multigroup analysis.

The data are included in piecewiseSEM so let’s load it:

data(meadows)

First, let’s construct the “free” model in lavaan:

jutila_model <- '
rich ~ elev + mass
mass ~ elev
'

jutila_lavaan <- sem(jutila_model, meadows, group = "grazed")

summary(jutila_lavaan)
## lavaan 0.6-3 ended normally after 53 iterations
##
##   Optimization method                           NLMINB
##   Number of free parameters                         14
##
##   Number of observations per group
##   1                                                165
##   0                                                189
##
##   Estimator                                         ML
##   Model Fit Test Statistic                       0.000
##   Degrees of freedom                                 0
##
## Chi-square for each group:
##
##   1                                              0.000
##   0                                              0.000
##
## Parameter Estimates:
##
##   Information                                 Expected
##   Information saturated (h1) model          Structured
##   Standard Errors                             Standard
##
##
## Group 1 [1]:
##
## Regressions:
##                    Estimate   Std.Err  z-value  P(>|z|)
##   rich ~
##     elev               0.073    0.010    7.232    0.000
##     mass              -0.001    0.002   -0.424    0.672
##   mass ~
##     elev              -1.203    0.470   -2.559    0.010
##
## Intercepts:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich               7.169    0.708   10.126    0.000
##    .mass             260.855   26.764    9.746    0.000
##
## Variances:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich              12.459    1.372    9.083    0.000
##    .mass           28057.590 3089.039    9.083    0.000
##
##
## Group 2 [0]:
##
## Regressions:
##                    Estimate   Std.Err  z-value  P(>|z|)
##   rich ~
##     elev               0.088    0.011    7.988    0.000
##     mass              -0.007    0.001   -5.465    0.000
##   mass ~
##     elev              -3.274    0.554   -5.908    0.000
##
## Intercepts:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich              11.349    0.750   15.139    0.000
##    .mass             451.732   24.949   18.107    0.000
##
## Variances:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich              14.384    1.480    9.721    0.000
##    .mass           43567.994 4481.792    9.721    0.000

In this example, the model fit can’t be determined because the model is saturated (df = 0). This is key moving forward because constraining paths will free up degrees of freedom with which to evaluate model fit.

Let’s begin by constraining all paths:

jutila_lavaan2 <- sem(jutila_model, meadows, group = "grazed", group.equal = c("intercepts", "regressions"))

summary(jutila_lavaan2)
## lavaan 0.6-3 ended normally after 44 iterations
##
##   Optimization method                           NLMINB
##   Number of free parameters                         14
##   Number of equality constraints                     5
##
##   Number of observations per group
##   1                                                165
##   0                                                189
##
##   Estimator                                         ML
##   Model Fit Test Statistic                      98.261
##   Degrees of freedom                                 5
##   P-value (Chi-square)                           0.000
##
## Chi-square for each group:
##
##   1                                             41.124
##   0                                             57.136
##
## Parameter Estimates:
##
##   Information                                 Expected
##   Information saturated (h1) model          Structured
##   Standard Errors                             Standard
##
##
## Group 1 [1]:
##
## Regressions:
##                    Estimate   Std.Err  z-value  P(>|z|)
##   rich ~
##     elev    (.p1.)     0.072    0.008    9.077    0.000
##     mass    (.p2.)    -0.003    0.001   -2.629    0.009
##   mass ~
##     elev    (.p3.)    -2.527    0.364   -6.934    0.000
##
## Intercepts:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich    (.p7.)     8.965    0.556   16.119    0.000
##    .mass    (.p8.)   369.141   19.001   19.427    0.000
##
## Variances:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich              14.372    1.582    9.083    0.000
##    .mass           31207.882
##
##
## Group 2 [0]:
##
## Regressions:
##                    Estimate   Std.Err  z-value  P(>|z|)
##   rich ~
##     elev    (.p1.)     0.072    0.008    9.077    0.000
##     mass    (.p2.)    -0.003    0.001   -2.629    0.009
##   mass ~
##     elev    (.p3.)    -2.527    0.364   -6.934    0.000
##
## Intercepts:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich    (.p7.)     8.965    0.556   16.119    0.000
##    .mass    (.p8.)   369.141   19.001   19.427    0.000
##
## Variances:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich              17.997    1.851    9.721    0.000
##    .mass           47113.409
anova(jutila_lavaan2)
## Chi Square Test Statistic (unscaled)
##
##           Df    AIC    BIC  Chisq Chisq diff Df diff Pr(>Chisq)
## Saturated  0                0.000
## Model      5 6754.4 6789.2 98.261     98.261       5  < 2.2e-16 ***
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

The model is significantly different from the unconstrained model we fit previously, implying that some paths could be constrained. Moreover, by constraining the coefficients, we now have 5 degrees of freedom to evaluate model fit. However, it is a poor fit, implying that some path coefficients must vary among groups.

The next step is to sequentially relax and constrain paths:

jutila_model2 <- '
rich ~ elev + mass
mass ~ c("b1", "b1") * elev
'

jutila_lavaan3 <- sem(jutila_model2, meadows, group = "grazed")

anova(jutila_lavaan, jutila_lavaan3)
## Chi Square Difference Test
##
##                Df    AIC    BIC  Chisq Chisq diff Df diff Pr(>Chisq)
## jutila_lavaan   0 6666.2 6720.3 0.0000
## jutila_lavaan3  1 6672.2 6722.5 8.0301     8.0301       1   0.004601 **
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

The model is still a poor fit, and it is significantly different from the “free” model. In this case, we would conclude that the $$elev -> mass$$ path should not be constrained.

Let’s repeat for the next two paths:

# elev -> rich
jutila_model3 <- '
rich ~ c("b2", "b2") * elev + mass
mass ~ elev
'

jutila_lavaan4 <- sem(jutila_model3, meadows, group = "grazed")

anova(jutila_lavaan, jutila_lavaan4)
## Chi Square Difference Test
##
##                Df    AIC    BIC  Chisq Chisq diff Df diff Pr(>Chisq)
## jutila_lavaan   0 6666.2 6720.3 0.0000
## jutila_lavaan4  1 6665.1 6715.4 0.9477    0.94767       1     0.3303
# mass -> rich
jutila_model4 <- '
rich ~ elev + c("b3", "b3") * mass
mass ~ elev
'

jutila_lavaan5 <- sem(jutila_model4, meadows, group = "grazed")

anova(jutila_lavaan, jutila_lavaan5)
## Chi Square Difference Test
##
##                Df    AIC    BIC  Chisq Chisq diff Df diff Pr(>Chisq)
## jutila_lavaan   0 6666.2 6720.3 0.0000
## jutila_lavaan5  1 6673.6 6723.9 9.4642     9.4642       1   0.002095 **
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1

Of these two paths, it seems the first: $$elev -> rich$$, is not significantly different from the “free” model, implying that this path could be constrained. Oppositely, it seems the significant difference between the “free” model and one in which the $$mass -> rich$$ path is constrained is not supported

Let’s check the fit of the model with the one constrait on $$elev -> rich$$:

summary(jutila_lavaan4)
## lavaan 0.6-3 ended normally after 53 iterations
##
##   Optimization method                           NLMINB
##   Number of free parameters                         14
##   Number of equality constraints                     1
##
##   Number of observations per group
##   1                                                165
##   0                                                189
##
##   Estimator                                         ML
##   Model Fit Test Statistic                       0.948
##   Degrees of freedom                                 1
##   P-value (Chi-square)                           0.330
##
## Chi-square for each group:
##
##   1                                              0.435
##   0                                              0.513
##
## Parameter Estimates:
##
##   Information                                 Expected
##   Information saturated (h1) model          Structured
##   Standard Errors                             Standard
##
##
## Group 1 [1]:
##
## Regressions:
##                    Estimate   Std.Err  z-value  P(>|z|)
##   rich ~
##     elev      (b2)     0.080    0.007   10.717    0.000
##     mass              -0.000    0.002   -0.297    0.767
##   mass ~
##     elev              -1.203    0.470   -2.559    0.010
##
## Intercepts:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich               6.795    0.596   11.408    0.000
##    .mass             260.855   26.764    9.746    0.000
##
## Variances:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich              12.492    1.375    9.083    0.000
##    .mass           28057.590       NA
##
##
## Group 2 [0]:
##
## Regressions:
##                    Estimate   Std.Err  z-value  P(>|z|)
##   rich ~
##     elev      (b2)     0.080    0.007   10.717    0.000
##     mass              -0.008    0.001   -5.999    0.000
##   mass ~
##     elev              -3.274    0.554   -5.908    0.000
##
## Intercepts:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich              11.754    0.624   18.831    0.000
##    .mass             451.732   24.949   18.107    0.000
##
## Variances:
##                    Estimate   Std.Err  z-value  P(>|z|)
##    .rich              14.423    1.484    9.721    0.000
##    .mass           43567.993       NA

Now the model fits the data well (P = 0.330), and we have, through an iterative procedure of imposing and relaxing constraints, determined which paths differ among groups ($$elev -> mass$$, $$mass -> rich$$) and which do not ($$elev -> rich$$).

Now let’s confirm this by fitting the model in piecewiseSEM:

jutila_psem <- psem(
lm(rich ~ elev + mass, meadows),
)

multigroup(jutila_psem, group = "grazed")
##
## Structural Equation Model of jutila_psem
##
## Groups = grazed [ 1, 0 ]
##
## ---
##
## Global goodness-of-fit:
##
##   Fisher's C = 0 with P-value = 1 and on 0 degrees of freedom
##
## ---
##
## Model-wide Interactions:
##
##   Response   Predictor  Test.Stat DF P.Value
##       rich elev:grazed     3296.7  1  0.3358
##       rich mass:grazed     3296.7  1  0.0026 **
##       mass elev:grazed 14283672.9  1  0.0055 **
##
##  elev -> rich constrained to the global model
##
## ---
##
## Group [1] coefficients:
##
##   Response Predictor Estimate Std.Error  DF Crit.Value P.Value Std.Estimate
##       rich      elev   0.0731    0.0081 351     8.9882  0.0000       0.4967
##       rich      mass  -0.0007    0.0017 162    -0.4198  0.6752      -0.0291
##       mass      elev  -1.2028    0.4728 163    -2.5438  0.0119      -0.1954
##
##   c ***
##
##       *
##
## Group [0] coefficients:
##
##   Response Predictor Estimate Std.Error  DF Crit.Value P.Value Std.Estimate
##       rich      elev   0.0731    0.0081 351     8.9882       0       0.3933
##       rich      mass  -0.0072    0.0013 186    -5.4216       0      -0.3222
##       mass      elev  -3.2735    0.5571 187    -5.8764       0      -0.3948
##
##   c ***
##     ***
##     ***
##
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05    c = constrained

As in our analysis in lavaan, the multigroup function has identified the $$elev -> rich$$ path as the only one in which coefficients do not differ among groups (denoted by a c next to the output). Thus, in the output, that coefficient is the same between groups; otherwise, the coefficients vary depending on whether the meadows is grazed or ungrazed. Moreover, it seems some of the paths differ in their statistical significance: the $$rich -> mass$$ is not significant in the grazed meadows, but is significant in the ungrazed meadows. So not only do the coefficients differ, but the model structure as well!

You’ll note that the piecewiseSEM output does not return a goodness-of-fit test because the model is saturated (i.e., no missing paths). While constraints are incorporated in terms of offsets (i.e., fixing model coefficients), unlike global estimation, this does not provide new information with which to test goodness-of-fit. This is a limitation of local estimation that extends beyond multigroup modeling to any piecewise model.

To draw inference about the study system, we would say that two paths differ among groups and one path does not. We would then report the two path models parameterized using the coefficient output (with the $$elev -> rich$$ path having the same coefficient in both groups). We would conclude that richness is affected by elevation and biomass under ungrazed conditions, but not under grazed conditions, where only elevation directly influences richness.

## 6.5 References

Grace, J. B., & Jutila, H. (1999). The relationship between species density and community biomass in grazed and ungrazed coastal meadows. Oikos, 398-408.